Quantcast Math Help! Find four consecutive integers such that the sum of the second and - XP Math - Forums
XP Math Home Sign Up FREE! | Sign In | Classroom Setup | Common Core Alignment PDF Version

Go Back   XP Math - Forums > Welcome > Off-Topic Discussion

 
 
Thread Tools Display Modes
Old 07-25-2007   #1
tallbond23
Guest
 
Posts: n/a
Default Math Help! Find four consecutive integers such that the sum of the second and

fourth is 132.? Really need help with this.Thanks in advance!
 
Old 07-25-2007   #2
jsoos
Guest
 
Posts: n/a
Default

64, 65, 66, 67
 
Old 07-25-2007   #3
forestevergreen
Guest
 
Posts: n/a
Default

So assign the 4 integers:x, x+1, x+2 and x+3so x+1 and x+3 equal 132x+1 + x+3 = 132 (combine like terms)2x + 4 = 132 (subtract 4 from each side)2x = 128 (divide by the number in front of x)x = 64So the numbers would be 64, 65, 66 and 67
 
Old 07-25-2007   #4
vicky
Guest
 
Posts: n/a
Default

let the smallest of those integers be x.since they are all consecutivethe integers are x, x+1, x+2 , x+3adding second and fourth integer=> (x+1) + (x+3) = 132=> 2*x + 4 = 132=> 2*x = 128=> x = 64therefore the intergers are64,65,66,67
 
 

Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off

Forum Jump


All times are GMT -4. The time now is 06:15 PM.


Powered by vBulletin® Version 3.8.11
Copyright ©2000 - 2020, vBulletin Solutions Inc.
XP Math