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Old 07-27-2007   #1
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Default math help SOS?

I need a general term for the following sequences...2/3, 3/4, 4/5, 5/6, 6/7 the next one is -3, 6, -9, 12, -15 and the last one is 3, 9, 27, 81, 243 thanx for all who help me with these you all are true angels muahz whoever answers the best gets best answer
Old 07-27-2007   #2
Teh Pwnzor
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First one is 1+n/2+n, n being the number in the sequence.Second one is (-1^n) x (3n), n being the number in the sequence.Third is 3^n, n being the number in the sequence.Hope that helps and good luck.
Old 07-27-2007   #3
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2/3, 3/4, 4/5, 5/6, 6/7nth term will be (n+1)/(n+2)-3, 6, -9, 12, -15nth term: 3*n*(-1)^n3, 9, 27, 81, 243nth term: 3^n
Old 07-27-2007   #4
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The i th. number in the following sequences are - First sequence: i/(i+1)Second sequence: ((-1)^i)*3*iThird sequence: 3^i

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