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Old 07-27-2007   #1
Canadia
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Default Circle Geometry?

Prove that the line x - 3y + 24=0 passes through the center of the circle given by x^2 + y^2 - 12x - 12y + 27 = 0I typed the circle's equation wrong. it should bex^2 + y^2 + 12x -12y +27 =0
 
Old 07-27-2007   #2
zohairf
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x^2 + y^2 - 12x - 12y + 27 = 0eqv. to (x-6)^2+(y-6)^2=36+36-27Thus the center is the point (6,6)6-3*6+24=0 must be trueSo your quesition is wrong.
 
 

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