Quantcast Circle Geometry? - XP Math - Forums
XP Math Home Sign Up FREE! | Sign In | Classroom Setup | Common Core Alignment PDF Version

Go Back   XP Math - Forums > Welcome > Off-Topic Discussion

Thread Tools Display Modes
Old 07-27-2007   #1
Posts: n/a
Default Circle Geometry?

Prove that the line x - 3y + 24=0 passes through the center of the circle given by x^2 + y^2 - 12x - 12y + 27 = 0I typed the circle's equation wrong. it should bex^2 + y^2 + 12x -12y +27 =0
Old 07-27-2007   #2
Posts: n/a

x^2 + y^2 - 12x - 12y + 27 = 0eqv. to (x-6)^2+(y-6)^2=36+36-27Thus the center is the point (6,6)6-3*6+24=0 must be trueSo your quesition is wrong.

Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off

Forum Jump

All times are GMT -4. The time now is 05:16 PM.

Powered by vBulletin® Version 3.8.11
Copyright ©2000 - 2020, vBulletin Solutions Inc.
XP Math