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08012007  #1 
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I need help for algebra !!! Please give me answers?
I need answers for these questions and I really need help!! Please helpayb=c solve for ya(y+1)=b solve for yax+b=cx solve for xay+z=amny solve for yThe digits below are in a special order. What order is it? 0,2,3,6,7,1,9,4,5,8

08012007  #2 
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PROBLEM 1:ay  b = cfirst add "b" to both sides... like this...(ay  b) + b = c + bnow combine "like" terms... to get...ay = c + bnow divide both sides by "a"(ay)/a = (c + b) / a.... and the "a's" cancel out on the left side...y = (c + b) / aPROBLEM 2:a(y+1)=b solve for ya * y + a * 1 = bay + a = bnow SUBTRACT "a" from both sides... like this...(ay + a)  a = b  acombine "like" terms... to get...ay = b  anow divide both sides by "a"(ay)/a = (b  a) / a.... and the "a's" cancel out on the left side...y = (b  a) / ay = b/a  a/ay = b/a  1PROBLEM 3:ax+b=cx solve for xyou want to move all the x's to either the left or right side...I'm going to move them to the left side...ax + b = cxsubtract "cx" from both sides... like this...(ax + b)  cx = cx  cxcombine "like" terms to get...ax + b  cx = 0now subtract "b" from both sides... like this...(ax + b  cx)  b = 0  bcombine "like" terms... to get...ax  cx = bnow factor out x on the left side.... like this...x(a  c) = bnow divide both sides by "(ac)"... like this...x(a  c) / (ac) = b / (a  c)the (ac)'s on the left cancel each other out...and you are left with...x =  b / (a  c)PROBLEM 4:ay + z = am  nyyou want to get all the y's on one side... I will put them all on the left side...ay + z = am  nyadd "ny" to both sides...(ay + z) + ny = (am  ny) + nycombine like terms...ay + z + ny = amsubtract "z" from both sides...(ay + z + ny)  z = am  zcombine like terms...ay + ny = am  zfactor "y" on left side...y (a + n) = am  zdivide both sides by (a+n)y = (am  z) / (a + n)PROBLEM 5:0, 2, 3, 6, 7, 1, 9, 4, 5, 8...They are 1digit numbers in reversed alphabetical orderZero, Two, Three, Six, Seven, One, Nine, Four, Five, Eight...

08012007  #3 
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the process of the guy above is right the answers1 y=(c+b)/a2 y=b/a 13 b/(ca)=x4 y=(amz)/(a+n)5 sorry dont remember that

08012007  #4 
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ayb=cay=c+by=(c+b)/aa(y+1)=by1=b/ay=(b/a)1ax+b=cxaxcx=bx(ac)=bx=b/(ac)ay+z=amnyay+ny=amzy(a+n)=amzy=(amz)/(a+n)i hope can help u larr...another one i also donno..

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