Quantcast algebra help? - XP Math - Forums
XP Math Home Sign Up FREE! | Sign In | Classroom Setup | Common Core Alignment PDF Version

Go Back   XP Math - Forums > Welcome > Off-Topic Discussion

 
 
Thread Tools Display Modes
Old 08-04-2007   #1
THE MAN!
Guest
 
Posts: n/a
Default algebra help?

factor completely with respect to the integers.-2x^3-4x^2-3x-6
 
Old 08-04-2007   #2
genius
Guest
 
Posts: n/a
Default

-2x^3-4x^2-3x-6you can solve tis by synthetic divisionmultiply by - on both sidetake the coeff of x^3,x^2,x and the constant 6and do synthetic divisionthe answer is (x+2)(2x^2+3)
 
Old 08-04-2007   #3
Ryan R
Guest
 
Posts: n/a
Default

-2x^3-4x^2-3x-6Use the grouping method since there are 4 terms(-2x^3-4x^2)+(-3x-6)Now factor out like terms in each group-2x^2(x+2)-3(x+2)Since the terms inside the ( ) are equal, that is a factorTake the numbers outside the ( ) and that is another term(-2x^2-3)(x+2)You can also take the negative out of the first term to get-(2x^2+3)(x+2)The first term does not factor any more, so your answer is:-(2x^2+3)(x+2)
 
 

Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off

Forum Jump


All times are GMT -4. The time now is 09:27 PM.


Powered by vBulletin® Version 3.8.11
Copyright ©2000 - 2020, vBulletin Solutions Inc.
XP Math