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07162007  #1 
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please help me with this math question?
Write an equation of a line that is perpendicular to y = 2x + 3 and passes through (3,4).how do you guys get these answers?...do you solve them by yourselfs or do u use a website?

07162007  #2 
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y  4 = (1/2)(x3), in pointslope formReason: (1/2)(2) = 1. If one slope is 2, then the other one must be 1/2 if the two lines are perpendicular to each other.

07162007  #3 
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Y=5x+3?

07162007  #4 
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y = (1/2)x + 11/2

07162007  #5 
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y = 2x + 3so the slope of this line is m = 2the slope of line perpendicular this line is m = 1/2if it passes through (3,4) therefore(y  y1) = m (x  x1)(y  4) = (1/2)(x  3)2y = x + 11

07162007  #6 
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y = 1/2x + 5/2

07162007  #7 
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y=1/2(x)+k thru (3,4) makes k=11/2

07162007  #8 
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y=2x+b4=2(3)+b4=6+b4+6=b10=by=2x+101) You want a perpendicular line, so try the negative slope...and then substitue x and y with your coordinates. Then, solve for B. (3,4) does go through the line, and does intersect.

07162007  #9 
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It is easy.the eq.is modified like this..2xy+3=0 equationof a perpendicular st.line is bxay+c=0.For this line it is x+2y+c=0.it passes through (3,4) so apply it.And the equation becomes 3+2(4)+c=0 so 3+8+c = 0.and so c= 11. therefore the eqution of the line is x+2y11=0i.e.,x+2y=11.The key point for this sum is the formula.Remember equation of a st. line perpendicular to a line with equation ax+by+k=0 is bxay+c=0.ALL THE BEST.

07162007  #10 
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how do we "guys" get these answers? When we didn't understand, we asked the teacher for help, instead of asking random people to do our homework for us.

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