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Old 08-04-2007   #1
zozo z
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Default Coordinate Geometry?

A curve is such that dy/dx = 4/√(6 - 2x) , and the P(1,8) is a point on the curve.The normal to the curve at the point P meets the coordinate axes at Q and R. Find the coordinates of the mid-point of QR
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Old 08-04-2007   #2
Lang Tu
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Hint:At P, the slope of the tangent is given by dy/dx = 2The normal will have slope - 1/2Its equation is then y = - 1/2 x + bYou can find b, knowing the line goes through P (1, 8)Then you can find Q (let x = 0) and R (let y = 0)and of course, the midpoint of QRGood luck
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