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 10-08-2008 #1 ihatemath14 Guest   Posts: n/a Negatives omg!!! heres the problem... -13xy x 40j=?
 10-20-2008 #2 hunter34 Guest   Posts: n/a $ \begin{eqnarray*} -13xy\cdot40j&=&(-13\cdot40)jxy\\ &=&-520jxy \end{eqnarray*}$
12-13-2008   #3
tom

Join Date: Dec 2008
Posts: 2

Quote:
 Originally Posted by ihatemath14 heres the problem... -13xy x 40j=?
If you want to look into negative numbers in more detail go to http://www.mathmadesimple.com and consider lesson 105, Rules for Integers and Absolute Value. This downloadable lesson deals with negative numbers, add, subtract, multiply, divide as well as negative fractions and absolute value.

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