Introductory Use the digits from 0 through 9

[Yiwan]

Can you use the digits from 0 through 9 - using any of the four operations, addition, subtraction, multiplication and division - so that when you do the math you get 100? Each number can be used only once, but you can use them in any order that you like.

[╒(σ_σ)╝]

(6+4)*5*2

Is that it?

I'm not sure if i understand your problem completly, can we use an operation more than once?

[Yiwan]

Originally Posted by ╒(σ_σ)╝

(6+4)*5*2

Is that it?

I'm not sure if i understand your problem completly, can we use an operation more than once?

mmm.... not at all.... You have to use all number through 0 to 9. You only use 2, 4, 5 and 6.....

Try again!

[jimjim]

I MIGHT BE SMART NUT I DONT KNOW THE ANSWER TO THAT ONE.

[Yiwan]

Originally Posted by jimjim

I MIGHT BE SMART NUT I DONT KNOW THE ANSWER TO THAT ONE.

Come on! You can do it Try to do it!

Hmmm here is something that works

10*(9/(7+2))*(8/(3+5))*(4+6)

[jawedraj86]

Originally Posted by Yiwan

Can you use the digits from 0 through 9 - using any of the four operations, addition, subtraction, multiplication and division - so that when you do the math you get 100? Each number can be used only once, but you can use them in any order that you like.

Solution:
"(9*8)+(7*2)+(4*3)+6-5+1-0=100"

[math_lover]

what about :



i can't write mixed fractions

with my best wishes

zigzag5552@Yahoo.com

[taziafreemon]

Originally Posted by Yiwan

Can you use the digits from 0 through 9 - using any of the four operations, addition, subtraction, multiplication and division - so that when you do the math you get 100? Each number can be used only once, but you can use them in any order that you like.

yeah i can so come and challenge me

Is there a formula for calculating the number of digits in a large number?

An example would be 218477