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06212009  #1 
Join Date: Jun 2009
Posts: 1

The conical water carrier
The figure shows a conical water carrier. it is filled to 25%.
How high does the water reach? Last edited by Mr. Hui; 06222009 at 07:38 AM.. 
07042009  #2  
Join Date: Dec 2008
Posts: 249

Quote:
V = (1/3)*pi*(r^2)*h So the volume of the entire water carrier is: V = (1/3)*pi*(16^2)*96 = 25,735.927 cm^3 If the carrier is only filled up to onefourth of its volume then: (1/4)*25,735.927 = 6433.982 cm^3 Then to solve for the height: 6433.982 = (1/3)*pi*(16^2)*h h = 24 cm. So the water reaches up 24 cm in the carrier, or onefourth the height of the carrier. 

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