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Old 07-06-2009   #1
Last
 
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hello i am new at this site, so i am hoping i can get help b4 this evenings class.
i have a problem i am not able to correctly solve.
it goes like this

Find 3 consecutive even integers such that 15 times the largest is 136 more than 4 times the sum of the smaller ones.
can you please show me the work so that i can compare it to what i did
thank you
Theresa
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Old 07-08-2009   #2
MAS1

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Quote:
Originally Posted by Last View Post
hello i am new at this site, so i am hoping i can get help b4 this evenings class.
i have a problem i am not able to correctly solve.
it goes like this

Find 3 consecutive even integers such that 15 times the largest is 136 more than 4 times the sum of the smaller ones.
can you please show me the work so that i can compare it to what i did
thank you
Theresa
HI Theresa:

Hope this does not come too late to help you.

Three consecutive even integers can be represented by n, n + 2, and n + 4.

15 x (n + 4) = 136 + 4 x (n + n + 2)
15n + 60 = 136 + 4 x (2n + 2)
15n + 60 = 136 + 8n + 8
15n + 60 = 8n + 144
15n - 8n = 144 - 60
7n = 84
n = 12

So the three consecutive even integers are 12, 14, and 16.

To check: 15 x 16 = 136 + 4 x (12 + 14)
240 = 136 + 4 x 26
240 = 136 + 104
240 = 240
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Old 07-13-2009   #3
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Red face thank you, I finally figured it out, it took all day to do so, but i did it,

Quote:
Originally Posted by MAS1 View Post
HI Theresa:

Hope this does not come too late to help you.

Three consecutive even integers can be represented by n, n + 2, and n + 4.

15 x (n + 4) = 136 + 4 x (n + n + 2)
15n + 60 = 136 + 4 x (2n + 2)
15n + 60 = 136 + 8n + 8
15n + 60 = 8n + 144
15n - 8n = 144 - 60
7n = 84
n = 12

So the three consecutive even integers are 12, 14, and 16.


To check: 15 x 16 = 136 + 4 x (12 + 14)
240 = 136 + 4 x 26
240 = 136 + 104
240 = 240
thankyou for your help, i had finally figured it out , it taken all day to do it, and i got it correct. i am having trouble with graphing, so i will post later on to get help with that , Thank you again
Last
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Old 07-13-2009   #4
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Red face Thank you

I hope you get this post, the problem i had done taken me a very long time to do but i did it and i got it correct, i am hoping to come back on later and get help with graphing, i am struggling with that one too much too fast,
Thanks again Last
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Old 09-09-2009   #5
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Unhappy sorry

Quote:
Originally Posted by Last View Post
hello i am new at this site, so i am hoping i can get help b4 this evenings class.
i have a problem i am not able to correctly solve.
it goes like this

Find 3 consecutive even integers such that 15 times the largest is 136 more than 4 times the sum of the smaller ones.
can you please show me the work so that i can compare it to what i did
thank you
Theresa
im sorry i cant help you. Id like to but i cant im not good at math and i dont really like it my mom made me sighn up hoping that i would get good at it i am really really sorry

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Old 10-06-2009   #6
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Unhappy fractinal equations HELP !!!!!!!!!!!!!!!!!

mr Hui,,,,, Are you available to help me understand some algebraic factoring please,, Example 3 over 2x + 2 + 4 over x + 1 = 11/12

Quote:
Originally Posted by MAS1 View Post
HI Theresa:




Hope this does not come too late to help you.

Three consecutive even integers can be represented by n, n + 2, and n + 4.

15 x (n + 4) = 136 + 4 x (n + n + 2)
15n + 60 = 136 + 4 x (2n + 2)
15n + 60 = 136 + 8n + 8
15n + 60 = 8n + 144
15n - 8n = 144 - 60
7n = 84
n = 12

So the three consecutive even integers are 12, 14, and 16.

To check: 15 x 16 = 136 + 4 x (12 + 14)
240 = 136 + 4 x 26
240 = 136 + 104
240 = 240
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Old 10-07-2009   #7
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Quote:
Originally Posted by Last View Post
mr Hui,,,,, Are you available to help me understand some algebraic factoring please,, Example 3 over 2x + 2 + 4 over x + 1 = 11/12
Is your equation:

3/(2x + 2) + 4/(x + 1) = 11/12

Then we can say
3/(2(x + 1)) + 4/(x + 1) = 11/12
3/(2(x + 1)) + 8/(2(x + 1)) = 11/12
(3 + 8)/(2(x + 1)) = 11/12
11/(2(x + 1) = 11/12
2(x + 1) = 12
x + 1 = 6
x = 5
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Old 01-28-2010   #8
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hello iim jessie27 can you help me with probability of independent events please
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Old 01-31-2010   #9
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Two events A and B are independent if the occurrence of one does not affect the probability of the occurrence of the other. For instance, the event of obtaining a head on the up face when a fair coin is tossed and the event of obtaining a five on the up face when a fair die is rolled are independent.
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Old 02-16-2010   #10
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hello iim jessie27 can you help me with probability of independent events please
Also If the outcome of those effects do not effect eachother in any shape or form, for example the outcome of flipping heads or rolling a six have nothing to do with eachother depending on the problem therefore making them independent of eachother.
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