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07072009  #1 
Join Date: Jul 2009
Posts: 1

Advanced Functions
Could Someone please help me...I have no idea what to do for these two promblems
For what values of k does the function f(x) = x3 + 6x2 + kx – 4 give the same remainder when divided by (x1) and (x + 2)? Determine the value of k when x3 + kx2 + 2x – 3 is divided by x + 2, and the remainder is 1. 
07092009  #2  
Join Date: Dec 2008
Posts: 249

Quote:
k + 3 = 12  2k 3k = 9 k = 3 2. Divide x^3 + kx^2 + 2x  3 by x + 2 giving x^2 + (k 2)x + (2  2(k  2)) with a remainder of 3  2(2  2(k 2)). Then set the remainder equal to 1 and solve for k. 3  2(2  2(k  2)) = 1 2(2  2k + 4) = 4 2  2k + 4 = 2 6  2k = 2 2k = 8 k = 4 

02222010  #3 
Join Date: Feb 2010
Posts: 388

1. Divide x^3 + 6x^2 + kx  4 by (x  1). This gives x^2 + 7x + (k + 7) with a remainder of k + 3. Then divide x^3 + 6x^2 + kx  4 by (x + 2).This gives x^2 + 4x + (k  8) with a remainder of 12  2k. Then set the two remainders equal to each other.
k + 3 = 12  2k 3k = 9 k = 3 2. Divide x^3 + kx^2 + 2x  3 by x + 2 giving x^2 + (k 2)x + (2  2(k  2)) with a remainder of 3  2(2  2(k 2)). Then set the remainder equal to 1 and solve for k. 3  2(2  2(k  2)) = 1 2(2  2k + 4) = 4 2  2k + 4 = 2 6  2k = 2 2k = 8 k = 4 
02242010  #4  
Join Date: Dec 2008
Posts: 249

Cut and Paste?
Quote:


02242010  #5 
Join Date: Feb 2010
Posts: 388

Lol i was seeing if u would catch that you did.*of) Course, The other post i didn't Cut and Paste Thou
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