Math 12 Assignment - due monday sept 21 - XP Math - Forums

 XP Math - Forums Math 12 Assignment - due monday sept 21

 09-19-2009 #1 jasishappy   Join Date: Sep 2009 Posts: 1 Math 12 Assignment - due monday sept 21 I have three questions that I don't get how to complete/start in a math assignment during the logarithm/exponent unit: here are the three questions (image link) http://img3.imageshack.us/img3/4051/mathassignment.png please message back if you can help with them
09-21-2009   #2
MAS1

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Quote:
 Originally Posted by jasishappy I have three questions that I don't get how to complete/start in a math assignment during the logarithm/exponent unit: here are the three questions (image link) http://img3.imageshack.us/img3/4051/mathassignment.png please message back if you can help with them
1. (sqrt(a))^3x = (a^(x^2))((a^(1/7))^(-5-2x))
a^(3x/2) = (a^(x^2))(a^(-(5/7)-(2x/7)))
a^(3x/2) = a^(x^2 -(2/7)x -(5/7))
(3/2)x = x^2 -(2/7)x -(5/7)
0 = x^2 -(25/14)x -(5/7)
Use quadratic formula to find x = 2.12 or -0.34

2. 2^(-1) = log9(logx(1/343))
(1/2) = log9(logx(1/343))
9^(1/2) = logx(1/343)
3 = logx(1/343)
x^3 = (1/343)
x = (1/7)
Note: The sqrt(9) = +3 and -3, but we cannot use -3 because it gives us x = 7 and if we plug it back into the original equation then we get log9(-3) which is not defined.

09-29-2009   #3
shirley

Join Date: Aug 2009
Posts: 3

Quote:
 Originally Posted by jasishappy I have three questions that I don't get how to complete/start in a math assignment during the logarithm/exponent unit: here are the three questions (image link) http://img3.imageshack.us/img3/4051/mathassignment.png please message back if you can help with them
i don't know that i'm just in 7th grade

 02-22-2010 #4 jmw106462 Last Achievements     Join Date: Feb 2010 Posts: 388 1. (sqrt(a))^3x = (a^(x^2))((a^(1/7))^(-5-2x)) a^(3x/2) = (a^(x^2))(a^(-(5/7)-(2x/7))) a^(3x/2) = a^(x^2 -(2/7)x -(5/7)) (3/2)x = x^2 -(2/7)x -(5/7) 0 = x^2 -(25/14)x -(5/7) . 2^(-1) = log9(logx(1/343)) (1/2) = log9(logx(1/343)) 9^(1/2) = logx(1/343) 3 = logx(1/343) x^3 = (1/343) x = (1/7)

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