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 Thread: Mathcounts Marathon View Single Post
 10-30-2007 #72 hunter34 Guest   Posts: n/a My attempt. You know that the surface area of the tetrahedron is $a^2\sqrt{3}$, making the side length $\frac{19}{\sqrt{3}}$. This gives the volume:$\frac{6859\sqrt{3^3}\sqrt{2}}{324}$ You all may laugh at this failing attempt.