x^23x10=0
that's how it starts (this is a quadratic equation)
then i factored
for exampla: (xm) (x+n)
and the original is ax^2+bx+c=0
m+n must equal b, and mn must equal c.
5 and 2 add
up to 3
and they multiply to get 10
therefore, it is (x5)(x+2)=0
either x5=0, or x+2=0
therefore x=5, or 2
now who do u think is going to win mathcounts?
do u get how i did it?
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