Quote:
Originally Posted by burgess
Help me to solve my algebra 1 homework on ages
The difference between the ages of two persons is 10 years. Fifteen years ago, the elder one was twice as old as the younger one. What is the present age of younger one?
Thanks

x = present age of elder person
y = present age of younger person
x  y = 10
(x  15) = 2(y  15)
x = 10 + y
(10 + y  15) = 2(y  15)
y  5 = 2y  30
5 = y  30
30  5 = y
25 = y
So the younger person is 25 and the older person is 35.