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**Dragonballful23** · 05-13-2013

Find the solution set for these:
${{x^2}+2x+1}=0$

${{3x^2}+4x+1}=0$

${{x^2}+3x}=-2$

This one is the hardest....

${{2x^2}+10x}=-15$

05-13-2013	#1
Dragonballful23 Join Date: Dec 2011 Posts: 386	Quadratic Equations Find the solution set for these: ${{x^2}+2x+1}=0$ ${{3x^2}+4x+1}=0$ ${{x^2}+3x}=-2$ This one is the hardest.... ${{2x^2}+10x}=-15$ __________________ Finally finished all my tests!!! I am ekko main now ^_^ (ign: supersaiyan2363) It's not how much time you have, it's how you use it. -Ekko Last edited by Mr. Hui; 05-13-2013 at 06:08 PM..