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Old 07-26-2014   #2

Join Date: Dec 2008
Posts: 249

Originally Posted by burgess View Post
Needed help to solve math home work problem

A can do 1/4 of a work in 10 days, B can do 40% of the work in 40 days and C can do 1/3 rd of the work in 13 days. If all three are working together, in how many day they can complete the total work?

Please tell me the procedure to solve the problem

A: Since A can do 1/4 of the job in 10 days then it takes A 40 days to finish the job. A's rate of work is 1/40
B: Since B can do 2/5 of the job in 40 days then it takes B 100 days to finish the job. B's rate of work is 1/100
C:Since C can do 1/3 of the job in 13 days then it takes C 39 days to finish the job. C's rate of work is 1/39

We can add together the rtes and find a combined rate of work for A, B, and C.

1/40 + 1/100 + 1/39 = 0.025 + 0.01 + 0.025641... = .060641025641...

To find the number of days we take the reciprocal giving us about 16.5 days.
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