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**Sillysidley** · 09-01-2007

No, it's
$2^{4^x}=2^{2(2^{x})}-><br /> 4^x=2^{x+1}-><br /> 2^{2x}=2^{x+1}-><br /> 2x=x+1-><br /> x=1$

09-01-2007	#61
Sillysidley Join Date: Oct 2006 Posts: 822	No, it's $2^{4^x}=2^{2(2^{x})}-><br /> 4^x=2^{x+1}-><br /> 2^{2x}=2^{x+1}-><br /> 2x=x+1-><br /> x=1$ __________________ .