x^2-3x-10=0
that's how it starts (this is a quadratic equation)
then i factored
for exampla: (x-m) (x+n)
and the original is ax^2+bx+c=0
m+n must equal b, and mn must equal c.
-5 and 2 add
up to -3
and they multiply to get -10
therefore, it is (x-5)(x+2)=0
either x-5=0, or x+2=0
therefore x=5, or -2
now who do u think is going to win mathcounts?
do u get how i did it?
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