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09162014  #1 
Join Date: Dec 2011
Posts: 386

Quadratic Easy
Easy quadratics (solve for x)
x^23x+2 x^24x+2 2x^25x+2
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Finally finished all my tests!!! I am ekko main now ^_^ (ign: supersaiyan2363) It's not how much time you have, it's how you use it. Ekko 
09222014  #2 
Join Date: Sep 2014
Posts: 1

[QUOTE=Dragonballful23;44096]Easy quadratics (solve for x)
1) x^23x+2 Splitting middle term of quadratic x^2x2x+2 x(x1)2(x1) (x1)(x2) x=1 and x=2. 2)x^24x+2 The Quadratic Formula: For ax^2 + bx + c = 0, the value of x is given by: x = [ b ± sqrt(b^2  4ac) ] / 2a a=1 , b= 4 , c= 2 x = [ 4 ± sqrt(4^2  4*1*2) ] / 2*1 x = [ 4 ± sqrt(16  8) ] / 2 x = [ 4 ± sqrt(8) ] / 2 x = [ 4 ± 2 sqrt(2) ] / 2 x = [ 2 ± sqrt(2) ] x = [ 2 + sqrt(2) ] and x = [ 2  sqrt(2) ] 3) 2x^25x+2 Splitting middle term of quadratic 2x^24xx+2 2x(x2)1(x2) (x2)(2x1) x = 2 and x = 1/2 
09272014  #3  
Join Date: May 2011
Posts: 86

Quote:
x^24x+2 can't be factored, so by the quadratic formula it's x = 4 +/ 8 all over 2, or x = 2 +/ root 2 2x^2 5x+2 can be factored as (2x1)(x2) = 0, or x = 1/2, 2
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09292014  #4 
Join Date: Dec 2011
Posts: 386

Nice Job!
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Finally finished all my tests!!! I am ekko main now ^_^ (ign: supersaiyan2363) It's not how much time you have, it's how you use it. Ekko 
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