07-16-2007 #1 Berry A Guest   Posts: n/a please help me with this math question? Write an equation of a line that is perpendicular to y = 2x + 3 and passes through (3,4).how do you guys get these answers?...do you solve them by yourselfs or do u use a website?
 07-16-2007 #2 sahsjing Guest   Posts: n/a y - 4 = (-1/2)(x-3), in point-slope form-------------Reason: (-1/2)(2) = -1. If one slope is 2, then the other one must be -1/2 if the two lines are perpendicular to each other.
 07-16-2007 #3 T.O. Guest   Posts: n/a Y=5x+3?
 07-16-2007 #4 MsMath Guest   Posts: n/a y = -(1/2)x + 11/2
 07-16-2007 #5 jed Guest   Posts: n/a y = 2x + 3so the slope of this line is m = 2the slope of line perpendicular this line is m = -1/2if it passes through (3,4) therefore(y - y1) = m (x - x1)(y - 4) = -(1/2)(x - 3)2y = -x + 11
 07-16-2007 #6 xjmox14x Guest   Posts: n/a y = -1/2x + 5/2
 07-16-2007 #7 rwbblb46 Guest   Posts: n/a y=-1/2(x)+k thru (3,4) makes k=11/2
 07-16-2007 #8 Michelle D Guest   Posts: n/a y=-2x+b4=-2(3)+b4=-6+b4+6=b10=by=-2x+101) You want a perpendicular line, so try the negative slope...and then substitue x and y with your coordinates. Then, solve for B. (3,4) does go through the line, and does intersect.
 07-16-2007 #9 Aishu Guest   Posts: n/a It is easy.the eq.is modified like this..2x-y+3=0 equationof a perpendicular st.line is bx-ay+c=0.For this line it is x+2y+c=0.it passes through (3,4) so apply it.And the equation becomes 3+2(4)+c=0 so 3+8+c = 0.and so c= -11. therefore the eqution of the line is x+2y-11=0i.e.,x+2y=11.The key point for this sum is the formula.Remember equation of a st. line perpendicular to a line with equation ax+by+k=0 is bx-ay+c=0.ALL THE BEST.
 07-16-2007 #10 b p Guest   Posts: n/a how do we "guys" get these answers? When we didn't understand, we asked the teacher for help, instead of asking random people to do our homework for us.

 Thread Tools Display Modes Hybrid Mode

 Posting Rules You may not post new threads You may not post replies You may not post attachments You may not edit your posts BB code is On Smilies are On [IMG] code is On HTML code is Off Forum Rules
 Forum Jump User Control Panel Private Messages Subscriptions Who's Online Search Forums Forums Home Welcome     XP Math News     Off-Topic Discussion Mathematics     XP Math Games Worksheets     Homework Help     Problems Library     Math Challenges

All times are GMT -4. The time now is 05:28 AM.

 Contact Us - XP Math - Forums - Archive - Privacy Statement - Top