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Common Core Alignment ![]() |
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#71 |
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![]() Yeah, a Platonic solid.
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#72 |
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![]() My attempt.
You know that the surface area of the tetrahedron is You all may laugh at this failing attempt. |
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#73 |
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![]() Next problem?
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#74 |
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![]() Wait is that right?
If |
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#75 |
![]() ![]() ![]() ![]() ![]() ![]() Join Date: Oct 2006
Posts: 822
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#76 |
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![]() Okay, so here's the next one:
The 9-digit number abb,aba,ba3 is a multiple of 99 for some pair of digits a and b. What is b - a ? |
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#77 |
![]() ![]() ![]() ![]() ![]() ![]() Join Date: Oct 2006
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![]() Using properties for divisibilities by 9 and 11, we determine
a+b is 6 mod 9 b-a is 4 mod 11. Since they are digits, b-a is 4.
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#78 |
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![]() Good.
What is the smallest multiple of 24 that is a perfect cube? |
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#79 |
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![]() (x+y)^6
Using Pascal's triangle, we could figure out the problem x^6 + 6*x^5*y + 15*x^4*y*2 + 20*x^3*y*3 + 15*x^2*y^4 + 6*x*y^5 + y^6 Do you notice a pattern? |
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#80 |
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![]() first, you factor 24 = 2^3 * 3
So the next perfect cube would be 2^a multiple of three * 3^3 The answer is 24 * 9, which is equal to 216 next question: WITH FULL SOLUTIONS PLEASE Fractions a/b and c/d are called neighbor fractions if their difference (ad - bc)/(bd) has a numerator of positive or negative 1, that is, ad - bc = positive or negative one. Prove that If a/b and c/d are neighbor fractions, then (a + b)/(c + d) is between them and is a neighbor fraction for both a/b and c/d; moreover, no fraction e/f with positive integer "e" and "f" such that f is less than b + d is between a/b and c/d. [/img] |
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