A problem on Wheel and revolutions

[burgess]

Help required to solve algebra 1 homework problem

A wheel that has 14 cogs is meshed with a smaller wheel of 6 cogs. When the smaller wheel has made 21 revolutions, then what is the number of revolutions made by larger wheel?

Thanks

[Dark88Dragon]

14 : 6 = x : 21

x = (21 * 6) / 14

You can count the cogs, 21 revolutions * 6 cogs = 126 cogs
Divide the whole number of cogs though the number of cogs on the larger wheel. They have the same distance on the larger wheel.
126 / 14 = 9

[MAS1]

Originally Posted by burgess

Help required to solve algebra 1 homework problem

A wheel that has 14 cogs is meshed with a smaller wheel of 6 cogs. When the smaller wheel has made 21 revolutions, then what is the number of revolutions made by larger wheel?

Thanks

If the small wheel makes 21 revolutions then it turns through 21 x 6 = 126 cogs.
The larger wheel then makes 126/14 = 9 revolutions