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 09-16-2014 #1 Dragonballful23     Join Date: Dec 2011 Posts: 386 Quadratic Easy Easy quadratics (solve for x) x^2-3x+2 x^2-4x+2 2x^2-5x+2 __________________ Finally finished all my tests!!! I am ekko main now ^_^ (ign: supersaiyan2363) It's not how much time you have, it's how you use it. -Ekko
 09-22-2014 #2 TutorSOS   Join Date: Sep 2014 Posts: 1 [QUOTE=Dragonballful23;44096]Easy quadratics (solve for x) 1) x^2-3x+2 Splitting middle term of quadratic x^2-x-2x+2 x(x-1)-2(x-1) (x-1)(x-2) x=1 and x=2. 2)x^2-4x+2 The Quadratic Formula: For ax^2 + bx + c = 0, the value of x is given by: x = [ -b ± sqrt(b^2 - 4ac) ] / 2a a=1 , b= -4 , c= 2 x = [ 4 ± sqrt(-4^2 - 4*1*2) ] / 2*1 x = [ 4 ± sqrt(16 - 8) ] / 2 x = [ 4 ± sqrt(8) ] / 2 x = [ 4 ± 2 sqrt(2) ] / 2 x = [ 2 ± sqrt(2) ] x = [ 2 + sqrt(2) ] and x = [ 2 - sqrt(2) ] 3) 2x^2-5x+2 Splitting middle term of quadratic 2x^2-4x-x+2 2x(x-2)-1(x-2) (x-2)(2x-1) x = 2 and x = 1/2
09-27-2014   #3
Pi=

Join Date: May 2011
Posts: 86

Quote:
 Originally Posted by Dragonballful23 Easy quadratics (solve for x) x^2-3x+2 x^2-4x+2 2x^2-5x+2
x^2-3x+2 = (x-2)(x-1) = 0, or the solutions are x = 2,1
x^2-4x+2 can't be factored, so by the quadratic formula it's
x = 4 +/- 8 all over 2, or x = 2 +/- root 2

2x^2 -5x+2 can be factored as (2x-1)(x-2) = 0, or x = 1/2, 2
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09-29-2014   #4
Dragonballful23

Join Date: Dec 2011
Posts: 386

Quote:
 Originally Posted by Pi= x^2-3x+2 = (x-2)(x-1) = 0, or the solutions are x = 2,1 x^2-4x+2 can't be factored, so by the quadratic formula it's x = 4 +/- 8 all over 2, or x = 2 +/- root 2 2x^2 -5x+2 can be factored as (2x-1)(x-2) = 0, or x = 1/2, 2
Nice Job!
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Finally finished all my tests!!!

I am ekko main now ^_^

(ign: supersaiyan2363)

It's not how much time you have, it's how you use it.
-Ekko

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