(x-4)(x-1),multiplying algebra expressions? - XP Math - Forums

 XP Math - Forums (x-4)(x-1),multiplying algebra expressions?

 07-20-2007 #1 missy prapjel Guest   Posts: n/a (x-4)(x-1),multiplying algebra expressions? pls i want someone who understands this concept very well to answer.
 07-20-2007 #2 YvesBenoit Guest   Posts: n/a (x-4)(x-1) Alright, there are 3 steps. Each of these steps will determine a "part" of the answer. First, take the first term, in this case, x. x Second, total up your integers. In this case, -4 + -1 = -5. Third, multiply both integers. -4 * -1 = 4. This gives x, -5, 4. Each part must be raised to the power of 2, 1, 0, respectively. Final answer (x^2) -5x + 4
 02-21-2010 #3 jmw106462     Join Date: Feb 2010 Posts: 388 x^2-5x+4 is the answer
 08-20-2013 #4 Dark88Dragon     Join Date: Aug 2013 Posts: 20 (x-4)*(x-1) = ((x*x) + x*(-1)) (+) ((-4)*x (+) (-4*(-1)) = x*x-x-4x+4 = x² - 5x + 4; for example: x = 10 ---> 10² - 5*10 + 4 = 100 - 50 + 4 = 54; I hope that was not too complicated
11-29-2013   #5
Jonathan W

Join Date: Jan 2012
Posts: 318

Quote:
 Originally Posted by missy prapjel pls i want someone who understands this concept very well to answer.
I know this thread is dead, but since someone revived it, I might as well answer it.

I think you can factor this by using the Distributive Property. So, (x - 4)(x - 1) would become x(-4 - 1)

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