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01152008  #1 
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math
2x+5/5=3x+1/2+x+7/2

01212008  #2 
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2x+5/5=3x+1/2+x+7/2
is this how it should look? because i can only figure from what you typed (2x+5)/5 = (3x+1)/2 + (x+7)/2 if it does then combine the right side together since both expressions have common denominator of 2. then you should have (2x+5)/5 = (3x+1+x+7)/2 (2x+5)/5 = (2x+8)/2 Now you can cross multiply because you have a fraction equal to a fraction (2x+5) *times* 2 = (2x+8) *times* 5 4x+10 = 10x+40 now bring all variable (x) to one side and constant to the other. I want to bring 4x to the right and 40 to the left. I would have: 4x + 10 = 10x + 40 4x 40 =4x 40 30 = 6x divide 6 to both sides 30=6x 6 = 6 you should get: x=5 Check your work by plug 5 back into the original equation to see if it is correct. Hope that helps 
01232008  #3 
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go me
good explation fav dog u are really good in math why dont you challenge me

01292008  #4 
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challenge you at what? I am new here so tell me what's going on.

01292008  #5 
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you go to my pro file then you go to my last post and then you click on my last post i did then on the bottom its going to say challenge galal95
thats it 
05132008  #6 
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It's pretty much the same as the first reponse's:
(2x+5)/5 = (3x + 1)/2 + (x + 7)/2 =4x+10 = 15x+55x+35 (by multiplying both sides by 10) = 4x + 10 = 10x + 40 (simplification) =6x = 30 x=5 DONE!!! 
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