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#1 |
Join Date: Jun 2014
Posts: 14
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![]() Help required solve math homework problem
What is the least number that should be added to 2497 so that the total is exactly divisible by 5, 6, 4 and 3? Thanks |
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#2 |
Join Date: Aug 2013
Posts: 20
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![]() The number is the number of the illuminati, 23. This would mean the next number dividable by 3,4,5,6 is 2497+23 = 2520.
3*4*5*6 = 360 ==> 2520 / 360 = 7 180 would also work out because "360/180 equals 6/3". |
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#3 | |
![]() ![]() ![]() Join Date: Dec 2008
Posts: 249
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![]() Quote:
For a number to be divisible by 3 the sum of the number's digits should be divisible by 3. For a number to be divisible by 4 the last 2 digits of the number should be divisible by 4. For a number to be divisible by 5 the last digit of the number should be either 0 or 5. For a number to be divisible by 6 the number should be even and diviisble by 3. So to be divisible by 5 we could add 3 to 2497 giving 2500. 2500 is divisible by 5 and 4, but not 3 or 6. So we keep adding 10. The next number to try would be 13. 2497 + 13 = 2510. 2510 is not divisible by 3. Let's try adding 23. 23 + 2497 = 2520. 2520 is divisible by 3, 4, 5, and 6. Our answer is 23. |
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#4 |
Join Date: Dec 2014
Posts: 6
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![]() Taking the LCM of numbers 3, 4, 5, and 6 we get 60
Then dividing 2497 by 60 we get 41 with 37 remaining Means we have to add 23 to 37 to be 60 and to 2497 to be completely divide by 60 or 3, 4, 5, and 6. The answer is 23. |
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#5 |
Join Date: Jul 2019
Posts: 2
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![]() You should do some game programming tutorials to get to know the logical conceptions of incremental thinking - that knowledge will solve your beginner problem then
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