Problem on ages - XP Math - Forums

 XP Math - Forums Problem on ages

 06-27-2014 #1 burgess   Join Date: Jun 2014 Posts: 14 Problem on ages Help me to solve my algebra 1 homework on ages The difference between the ages of two persons is 10 years. Fifteen years ago, the elder one was twice as old as the younger one. What is the present age of younger one? Thanks
 07-10-2014 #2 Dark88Dragon     Join Date: Aug 2013 Posts: 20 x = the younger one x + 10 = (x * 2) -15 -x = -25 x = 25 The younger one is 25 now, 15 years ago he was 10 and the older one 20
07-10-2014   #3
MAS1

Join Date: Dec 2008
Posts: 249

Quote:
 Originally Posted by burgess Help me to solve my algebra 1 homework on ages The difference between the ages of two persons is 10 years. Fifteen years ago, the elder one was twice as old as the younger one. What is the present age of younger one? Thanks
x = present age of elder person
y = present age of younger person

x - y = 10

(x - 15) = 2(y - 15)

x = 10 + y

(10 + y - 15) = 2(y - 15)
y - 5 = 2y - 30
-5 = y - 30
30 - 5 = y
25 = y

So the younger person is 25 and the older person is 35.

 12-15-2014 #4 WilliamRVogl   Join Date: Dec 2014 Posts: 6 Considering the age of younger one is X age of younger one = x the the age of older one = x+10-----> eqn1 15 years ago age of younger one = x-15 age of older one = 2*(x-15) With eqn1 2*(x-15) = x+10-15 -> 2x-30 = x-5 -> 2x-x = -5+30 -> x = 25 X=25 is the present age of younger person and 25+10=35 is teh age of older person.

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